如何实现 chunk 函数，数组进行分组
更多描述 示例如下：
// => [[1, 2, 3], [4, 5, 6], [7]]
chunk([1, 2, 3, 4, 5, 6, 7], 3);Issue 欢迎在 Gtihub Issue 中回答此问题: Issue 661 (opens in a new tab)
Author 回答者: shfshanyue (opens in a new tab)
function chunk(list, size) {
const l = [];
for (let i = 0; i < list.length; i++) {
const index = Math.floor(i / size);
l[index] ??= [];
l[index].push(list[i]);
}
return l;
}或者直接构造出每一个 chunk
function chunk(list, size) {
const l = [];
for (let i = 0; i < list.length; i += size) {
const chunk = list.slice(i, i + size);
l.push(chunk);
}
return l;
}Author 回答者: haotie1990 (opens in a new tab)
function chunk(array, limit) {
limit = array.length <= limit ? array.length : limit;
const result = [];
while (array.length) {
result.push(array.splice(0, limit));
}
return result;
}Author 回答者: shfshanyue (opens in a new tab)
@haotie1990 这种实现方式很漂亮，但是有可能有副作用，当传入数组时，数组会被置空，可以先 [...array] 浅拷贝一份
Author 回答者: kirazZ1 (opens in a new tab)
function chunk(list = [], size) {
return list.reduce((pre, cur) => {
const length = pre.length;
if (length === 0 || pre[length - 1].length === size)
return pre.concat([[cur]]);
else {
pre[length - 1].push(cur);
return pre;
}
}, []);
}