随机生成六位数的手机验证码(重复/不可重复)
更多描述 字节跳动面经一道面试题,见 https://juejin.cn/post/6959364219162607630
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Issue 欢迎在 Gtihub Issue 中回答此问题: Issue 663
Author 回答者: shfshanyue
const random = (n) => Math.floor(Math.random() * (n + 1));
// 可生成重复的随机验证码
function randomCode() {
return [0, 0, 0, 0, 0, 0].map(() => random(9));
}
// 不可生成重复的随机验证码
const shuffle = (list) => list.sort((x, y) => Math.random() - 0.5);
const randomUniqueCode = () =>
shuffle([0, 1, 2, 3, 4, 5, 6, 7, 8, 9]).slice(0, 6);
// 一种比较低效的解法
function randomUniqueCode2() {
let i = 0;
let l = [];
while (i < 6) {
const x = random(9);
if (!l.includes(x)) {
i++;
l.push(x);
}
}
return l;
}
Author 回答者: real-jacket
// 不可重复
const numArr = [];
while (numArr.length < 6) {
let num = parseInt(Math.random() * 10);
if (numArr.indexOf(num) === -1) {
numArr.push(num);
}
}
Author 回答者: heretic-G
function sample(length) {
let arr = Array(100)
.fill(1)
.map((_, i) => (i / 10) | 0);
return shuffle(arr, length);
}
function notSample(length) {
let arr = Array(10)
.fill(1)
.map((_, i) => i);
return shuffle(arr, length);
}
function shuffle(arr, length) {
let index = 0;
while (index < length) {
let changeIndex = arr.length - 1 - index;
let randomIndex = Math.round(Math.random() * (changeIndex - 1));
let temp = arr[changeIndex];
arr[changeIndex] = arr[randomIndex];
arr[randomIndex] = temp;
index += 1;
}
return arr.slice(arr.length - length).join("");
}
Author 回答者: liunengnengneng
//可重复的 function liunum() { let yanzheng = ” for (let i = 0; i < 6; i++) { let num = Math.floor(Math.random()*10) yanzheng += num } return yanzheng } let num = liunum() console.log(‘重复的’,num); //不可重复的 function liunum1() { let yanzheng1 = ” for (let j = 0; j < 6; j++) { let num1 = Math.floor(Math.random()*10) if (yanzheng1.indexOf(num1)==-1)yanzheng1 += num1 else j—; } return yanzheng1 } let num1 = liunum1() console.log(‘不重复的’,num1);
Author 回答者: 1wkk
const randTo = (n: number) => ~~(Math.random() * (n + 1));
const shuffle = (list: Array<any>) => list.sort(() => Math.random() - 0.5);
// 随机生成六位数的手机验证码(重复/不可重复)
const vc = ({ len = 6, repeat = true } = {}) => {
if (len > 10 && repeat === false) {
throw new Error("len should less equal than 10 if repeat is false");
}
if (repeat) {
return Array(len)
.fill(0)
.map(() => randTo(9));
} else {
return shuffle([...Array(10).keys()]).slice(0, len);
}
};
console.log(vc());
console.log(vc({ len: 9 }));
console.log(vc({ repeat: false }));
console.log(vc({ len: 9, repeat: false }));
console.log(vc({ len: 11, repeat: false }));
Author 回答者: createhappymemoryforlife
const random = (length) => Math.floor(Math.random() * length);
// 重复
const randomCode = () => {
return [...new Array(6)].map((i) => random(10));
};
// 不重复
const randomUniqueCode = () => {
let arr = [...new Array(10)].map((_, index) => index);
return [...new Array(6)].map((i) => {
const selectIndex = random(arr.length);
return arr.splice(selectIndex, 1)[0];
});
};