FizzBuzz，是否能被3或5整除
更多描述 输入一个整数，如果能够被3整除，则输出
Fizz
如果能够被5整除，则输出 Buzz
如果既能被3整数，又能被5整除，则输出 FizzBuzz
//=> 'fizz'
fizzbuzz(3);
//=> 'buzz'
fizzbuzz(5);
//=> 'fizzbuzz'
fizzbuzz(15);
//=> 7
fizzbuzz(7);Issue 欢迎在 Gtihub Issue 中回答此问题: Issue 702 (opens in a new tab)
Author 回答者: shfshanyue (opens in a new tab)
function fizzbuzz(n) {
if (n % 5 === 0 && n % 3 === 0) {
return "fizzbuzz";
} else if (n % 3 === 0) {
return "fizz";
} else if (n % 5 === 0) {
return "buzz";
}
return n;
}Author 回答者: heretic-G (opens in a new tab)
function fizzbuzz(n) {
let str = ''
if (n % 3 === 0) {
str += 'Fizz'
}
if (n % 5 ==0 0) {
str += 'Buzz'
}
return str || n
}
Author 回答者: borraken (opens in a new tab)
const fizzbuzz = (num)=>${num%3?'':'fizz'}${num%5?'':'buzz'}||num
Author 回答者: Yinzhuo19970516 (opens in a new tab)
function fizzbuzz(n) {
if (n % 5 === 0 && n % 3 === 0) {
return "FizzBuzz";
} else if (n % 5 === 0) {
return "Buzz";
} else if (n % 3 === 0) {
return "Fizz";
} else {
return n;
}
}Author 回答者: Hazel-Lin (opens in a new tab)
function fizzbuzz(number) {
return number % 3 === 0 && number % 5 === 0
? "fizzbuzz"
: number % 5 === 0
? "buzz"
: number % 3 === 0
? "fizz"
: number;
}Author 回答者: Ghaining (opens in a new tab)
function fizzbuzz(n) {
const fizz = n % 3 === 0 ? "fizz" : "";
const buzz = n % 5 === 0 ? "buzz" : "";
return fizz + buzz || n;
}